PENYELESAIAN SOAL-SOAL SUBNETING

1. host = 300
2n- 2 ≥300,  n =9
2^9 - 2 =510 

subnet mask :
11111111.11111111.11111110.0000000
Jawab : C. 255.255.254.0

2. Eth0 = 192.168.1.65/27
Subnetmask :11111111.11111111.11111111.11100000
Host = 25-2 = 30 host/subnet
Net = 23 - 2 =6 subnet
Net id range broadcast 192.168.1.0 192.168.1.1 – 192.168.1.30 192.168.1.31
192.168.1.32 192.168.1.33 – 192.168.1.62 192.168.1.63
192.168.1.64 192.168.1.65 – 192.168.1.96 192.168.1.95
Jawab : F. Address - 192.168.1.70
Gateway -192.168.1.65
D. Address - 192.168.1.82
Gateway -192.168.1.65

3. IP = 172.31.192.166
Subnet = 11111111.11111111.11111111.11111000
Host= 23-2= 6
Net Id = 25-2 =30
Range Net ID
172.31.192.0 172.31.192.1- 172.31.192.6 172.31.192.7
172.31.192.8 172.31.192.9- 172.31.192.14 172.31.192.15
…
172.31.192.160 172.31.192.161- 172.31.192.166 172.31.192.167
Jawab : E. 172.31.192.160

4. Tiap option ada penjelasannya
Jawab : D. 255.255.0.0

5. Range net ID
172.16.128.0 172.16.159.255 172.16.159.255
172.16.160.0 …….
Net id :160-128 = 32 = 25
Subnetmask : 11111111.11111111.11111000.00000000
Jawab : D. 172.16.128.0 dan 255.255.224.0

6. Ip : 223.168.17.167/29
Subnet : 11111111.11111111.11111111.11111000
Host Id =23-2=6 Host/subnet
range net ID
223.168.17.0 223.168.17.1 – 223.168.17..6 223.168.17.7
223.168.17.8 223.168.17.9 – 223.168.17.14 223.168.17.15
……..
223.168.17.160 223.168.17.161 - .166 223.168.17.167 Jawab : C. broadcast address

7. IP : 192.168.99.0/29 (Class C)
Subnet : 11111111.11111111.11111111.11111000
Host Id : 23-2 = 6 host/subnet
Net Id : 25-2 = 30 subnet Jawab : C. 30 networks / 6 hosts

8. IP : 192.168.4.0 (class C)
subnet : 255.255.255.224 = 11111111.1111111111.1111111.11100000
Host Id : 25-2 = 30 host/subnet

(dikurangi 2 dikarenakan digunakan untuk broadcast and loopback)
Jawab : C. 30

9. 27 host /subnet = 2n-2 ≥27 , n = 5
2^5-2=30 Jawab : C. 255.255.255.224

10. 14 host/subnet ,maka 2n-2 ≥14, n = 4 ,karena 24-2 = 14
Jumlah Host Id= 14 per subnet

subnetmask :11111111.11111111.1111111.11110000 Jawab : C. 255.255.255.240

11. Pada class B ,membutuhkan 100 networks
2n -2≥100, n = 7
Subnetmask : 11111111.11111111.11111111.10000000 = 255.255.255.128 Jawab : F. 255.255.255.128

12. IP = 172.32.65.13(Class B)
Default Mask = 255.255.0.0 Jawab :C. 172.32.0.0

13. IP :172.16.210.0/22
Subnet : 11111111.11111111.11.0000000
Host Id : 210-2= 1022
Net id range broadcast
172.16.0.0 172.16.1.0 – 172.16.2.0 172.16.3.0
172.16.4.0 172.16.5.0 – 172.16.6.0 172.16.7.0
……
172.16.208.0 172.16.209.0 - 210.0 172.16.211.0 Jawab : C. 172.16.208.0

14. IP 115.64.4.0/22
Subnet : 11111111.11111111.11111100.00000000
Host Id = 210-2 = 1022
Range net ID:

115.64.4.0 115.64.4.1 – 115.64.4.6 115.64.4.7
115.64.8.0 ……………. Jawab : B, C, E

15. IP : 200.10.5.68/28
Subnet : 11111111.11111111.11111111.11110000
Host Id : 24-2 =14
Range net ID
200.10.5.0 200.10.5.1 – 200.10.5.14 200.10.5.15
……
200.10.5.64 200.10.5.65 – 200.10.5.78 200.10.5.79 Jawab : C. 200.10.5.64

16. 172.16.0.0/19
Subnet : 11111111.11111111.11100000.00000000
Net Id : 23-2 = 6
Host Id: = 213 = 8190 /subnet Jawab : E. 8 subnets, 8190 hosts each
17. Class B, 500 subnet, setiap subnet digunakan 100 host, mask??
Subnet = 2N > 500, N = 9 (bit “1”)
Subnet = 11111111.11111111.11111111.10000000 = 255.255.255.128 Jawab : B. 255.255.255.128

18 . IP address 172.16.66.0/21
Subnet: 11111111.11111111.11111000.00000000 = 255.255.248. 0
Host: 256-248 = 8
Range net ID
172.16.0.0 172.16.1.0 - .6.0 172.16.7.0
172.16.64.0 172.16.65.0 - .70.0 172.16.71.0 Jawab : C. 172.16.64.0

19. Class B, 100 subnet & 500 host persubnet
Subnet = 2n > 100, n = 7 (bit 1)
Subnetmask :11111111.11111111.11111110.00000000 Jawab: B. 255.255.254.0

20. IP : 192.168.19.24/29
Subnet : 11111111.11111111.11111111.11111000 = 255.255.255.248
Host Id = 23-3 =6host /network
range net ID
192.168.19.0 192.168.19.1 - 192.168.19.6 192.168.19.7
192.168.19.24 192.168.19.25 - .30 192.168.19.31 Jawab : C. 192.168.19.26 255.255.255.248

21. subnet = 300 , Host = 50 host per subnet 

-26-2 =62 ≥50 ,11111111.11111111.11111111.11000000 =255.255.255.192

-27 -2 =126 ≥ 50 11111111.11111111.11111111.10000000 =255.255.255.128Jawab : B dan E

22. IP address 172.16.112.1/25
Subnet : 11111111.11111111.11111111.10000000 = 255.255.255.128
Host Id = 27- 2 =126
range net id
172.16.112.0 172.16.112.1- .126 172.16.112.127
172.16.112.128 dst Jawab : A. 172.16.112.0

23. host = 3350
Host 2n - 2 > 3350, n = 12
Subnet : 11111111.11111111.11111000.00000000 = 255.255.248.0 Jawab : C. 255.255.248.0

24. Subnet 172.16.17.0/22
Subnet : 11111111.11111111.11111100.00000000 = 255.255.255.252
Host: 256-252 = 4 Jawab : E. 172.16.18.255 255.255.252.0

25. ip: 172.16.112.1/20
Subnet: 11111111.11111111.11110000.00000000 = 255.255.240.0
Host n = 12 (bit “0”), 212 – 2 = 4094 Jawab : C. 4094

26. Prefix /27 Class C
11111111.11111111.11111111.11100000
Subnet 23-2=6
Host Id 25-2 = 30 subnet Jawab : D,E,F
27. Class B, 450 host per subnet
Host Id 2n - 2 > 450, n = 9
Subnetmask = 11111111.11111111.11111110.00000000 = 255.255.254.0 Jawab : C. 255.255.254.0

28. IP = 198.18.166.33/27
Subnetmask = 11111111.11111111.11111111.11100000 = 255.255.255.224
IP Address 198.18.166.65 dihubungkan dengan Eth0 gateway 198.18.166.33, maka harus mengikuti ethernetnya.
Blok Subnet = 256 – 224 = 32
32, 64, 96, 128, 160, 192 Jawab :

A. The host subnet mask is incorrect
B. The host IP address is on a different network from the Serial interface of the router.

LANGKAH UPDATE KERNEL PADA UBUNTU 9.10

Pertama kita masuk terminal
Untuk menentukan mirror yang akan digunakan ketikan perintah  "sudo gedit /etc/apt/sources.list"

maka akan terbuka tampilan halaman sources.list yang akan kita edit,isi dengan mirror yang kita inginkan seperti pada gambar di bawah ini..

Dan jangan lupa untuk save

Lalu kita ketikan perintah "sudo apt-get update" untuk mendapatkan update mirrornya.Lalu ketikkan "sudo apt-get upgrade" untuk menjalankan update tersebut.  Lalu akan keluar gambar seperti :

Ini adalah proses update yang memerlukan koneksi yang cukup baik, karena proses ini mengambil cukup banyak file.

Setelah proses ini selesai maka kernel ubuntu 9.10 telah selesai di update.